R=12p^2+156p

Solution for R=12p^2+156p equation:

=12R^2+156R

We move all terms to the left:

-(12R^2+156R)=0

We get rid of parentheses

-12R^2-156R=0

a = -12; b = -156; c = 0;
Δ = b2-4ac
Δ = -1562-4·(-12)·0
Δ = 24336
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$R_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$R_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{24336}=156$
$R_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-156)-156}{2*-12}=\frac{0}{-24}
=0
$
$R_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-156)+156}{2*-12}=\frac{312}{-24}
=-13
$